What is the maximum decimal value of a binary octet represented as 1111 1111?

Prepare for the CCNA exam with interactive Anki flashcards and multiple choice questions. Access explanations and hints with every question to ensure a comprehensive understanding and master your certification!

A binary octet consists of 8 bits, and it can represent values from 0 to 255 in decimal. In the representation of 1111 1111, each digit (bit) corresponds to a specific power of 2, specifically:

  • The first bit (from the right) is (2^0)
  • The second bit is (2^1)

  • The third bit is (2^2)

  • The fourth bit is (2^3)

  • The fifth bit is (2^4)

  • The sixth bit is (2^5)

  • The seventh bit is (2^6)

  • The eighth bit is (2^7)

In the binary representation 1111 1111, all bits are set to 1. Therefore, the calculation to convert it to decimal involves summing the values of each bit where a 1 is present:

[

2^7 + 2^6 + 2^5 + 2^4 + 2^3 + 2^2 + 2^1 + 2^0 = 128 + 64 + 32 + 16 + 8 + 4 + 2 +

Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy